ARITHMETIC OPERATIONS ON BINARY NUMBER
Binary arithmetic is simpler to learn because binary number system deals with only two digits - 0 and 1. Binary number perform all arithmetic operation such as Addition, Substraction, Multiplication and compliment as in decimal number system.
Binary Addition
The addition table for binary arithmetic consist of only the following four entries:
0+1=1
1+1=0 , plus a carry of 1 to the next column.
1011
+ 1100
10111
+ 1100
10111
1100
+1100
Binary Substraction
There are three ways to do substraction between binary numbers:-
1. Simple Substraction
2. Substraction using 1's Complement
3. Substraction using 2's Complement
Simple Substraction: The complete table of binary substraction is as follows:
0-0=0
0-1=1, borrow 1 from next column
1-0=1
1-1=0
1101
- 0101
1. Simple Substraction
2. Substraction using 1's Complement
3. Substraction using 2's Complement
Simple Substraction: The complete table of binary substraction is as follows:
0-0=0
0-1=1, borrow 1 from next column
1-0=1
1-1=0
1101
- 0101
1000
1001
- 0111
0010
Substraction using 1'st Complement
We can do substraction using 1's complement. the steps are gi ven below:-
1. First we have to change the 2nd number(which is to substract) into 1's complement.
2. Here 1's complement mean exchanging the digit value mean convert '1' into '0' and '0' into '1' .
3. and perform addition operation on first number and the converted 1's complement number.
4. if we get an extra bit then ignore the extra bit and add 1 in the get result (after addition) to get final result.
5. If we can't get an extra bit then we again do 1's complement to get final result.
0010
Substraction using 1'st Complement
We can do substraction using 1's complement. the steps are gi ven below:-
1. First we have to change the 2nd number(which is to substract) into 1's complement.
2. Here 1's complement mean exchanging the digit value mean convert '1' into '0' and '0' into '1' .
3. and perform addition operation on first number and the converted 1's complement number.
4. if we get an extra bit then ignore the extra bit and add 1 in the get result (after addition) to get final result.
5. If we can't get an extra bit then we again do 1's complement to get final result.
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